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Information for RPM python-pycurl-7.43.0.5-6.fc33.src.rpm

ID697384
Namepython-pycurl
Version7.43.0.5
Release6.fc33
Epoch
Archsrc
SummaryA Python interface to libcurl
DescriptionPycURL is a Python interface to libcurl. PycURL can be used to fetch objects identified by a URL from a Python program, similar to the urllib Python module. PycURL is mature, very fast, and supports a lot of features.
Build Time2020-08-15 03:33:24 GMT
Size226.27 KB
3c9293fb6531e8bf3026f267bf42baf2
LicenseLGPLv2+ or MIT
Buildrootf33-build-300020-56462
Provides
python-pycurl-debuginfo = 7.43.0.5-6.fc33
python-pycurl-debugsource = 7.43.0.5-6.fc33
python3-pycurl = 7.43.0.5-6.fc33
Obsoletes No Obsoletes
Conflicts No Conflicts
Requires
gcc
libcurl-devel
openssl-devel
python3-bottle
python3-devel
python3-nose
python3-setuptools
rpmlib(CompressedFileNames) <= 3.0.4-1
rpmlib(FileDigests) <= 4.6.0-1
vsftpd
Recommends No Recommends
Suggests No Suggests
Supplements No Supplements
Enhances No Enhances
Files
1 through 3 of 3
Name ascending sort Size
0002-python-pycurl-7.43.0-tls-backend.patch2.13 KB
pycurl-7.43.0.5.tar.gz211.79 KB
python-pycurl.spec15.51 KB
Component of No Buildroots