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new_package: make subpackages work when %{source_name} and Name: disagree 

Remove %new_package dependency on %{source_name} when creating subpackages by
suffix. This way those subpackages still work even when the packager set
%{source_name} to a value and Name: to another.

Arguably, the packager is severily conflicted, and does not know what he wants
to achieve, but this case is easy enough to accomodate by tweaking the decision
tree. So let’s just make things work instead of blaming the packager.
This commit is contained in:
Nicolas Mailhot 2020-05-23 13:31:41 +02:00
parent a52af8dced
commit 0cb7566d95
1 changed files with 17 additions and 22 deletions
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39
common.lua
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@ -259,34 +259,29 @@ local function new_package(source_name, pkg_name, name_suffix, first, verbose)
return
end
-- New processing
if name_suffix and not pkg_name then
pkg_name = name_suffix
if source_name then
pkg_name = source_name .. "-" .. name_suffix
end
end
if not pkg_name then
if not source_name then
rpm.expand([[
if not (pkg_name or name_suffix or source_name) then
rpm.expand([[
%{error:You need to set %%{source_name} or provide explicit package naming!}
]])
else
pkg_name = source_name
end
end
if not source_name then
source_name = pkg_name
end
if (pkg_name == source_name) then
safeset("source_name", source_name, verbose)
print(rpm.expand("Name: %{source_name}"))
if name_suffix then
print(rpm.expand("%package " .. name_suffix))
set("currentname", "%{source_name}-" .. name_suffix, verbose)
else
if source_name and first then
srcpkg(verbose)
if not source_name then
source_name = pkg_name
end
print(rpm.expand("%package -n " .. pkg_name))
if (pkg_name == source_name) then
safeset("source_name", source_name, verbose)
print(rpm.expand("Name: %{source_name}"))
else
if source_name and first then
srcpkg(verbose)
end
print(rpm.expand("%package -n " .. pkg_name))
end
set("currentname", pkg_name, verbose)
end
set("currentname", pkg_name, verbose)
end
return {